Rublev defeats Griekspoor in three sets in Beijing

Andrey Rublev defeated Tallon Griekspoor in the round of 32 at the China Open in Beijing, 6-4 5-7 7-6.

The decider went to a third set

Rublev took the opening set, but Griekspoor responded in the second and brought the match back to level terms. In the deciding set, the opponents reached a tiebreak, where the match finished in favor of the Russian.

In the statistical background of the match, the head-to-head stands out: according to api.tennis, Rublev now has four wins in five matches against Griekspoor. The Dutchman’s only victory in this rivalry came in Dubai in 2026.

Before Beijing, Rublev reached the final at the AITO Hangzhou Open, where he lost to Daniil Medvedev, 5-7 4-6. Griekspoor’s previous tournament ended in a defeat to Denis Shapovalov at the Chengdu Open, 4-6 6-7.